Z^2-Z+4iZ=2i-4

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Solution for Z^2-Z+4iZ=2i-4 equation: 


Simplifying
Z2 + -1Z + 4iZ = 2i + -4

Reorder the terms:
-1Z + Z2 + 4iZ = 2i + -4

Reorder the terms:
-1Z + Z2 + 4iZ = -4 + 2i

Solving
-1Z + Z2 + 4iZ = -4 + 2i

Solving for variable 'Z'.

Reorder the terms:
4 + -1Z + Z2 + -2i + 4iZ = -4 + 2i + 4 + -2i

Reorder the terms:
4 + -1Z + Z2 + -2i + 4iZ = -4 + 4 + 2i + -2i

Combine like terms: -4 + 4 = 0
4 + -1Z + Z2 + -2i + 4iZ = 0 + 2i + -2i
4 + -1Z + Z2 + -2i + 4iZ = 2i + -2i

Combine like terms: 2i + -2i = 0
4 + -1Z + Z2 + -2i + 4iZ = 0

The solution to this equation could not be determined.

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